How many grams are there in 2.3 x 10^24 atoms of silver?
I need to use dimensional analysis, and I'm not sure of the conversions I'd need to solve this problem.
Thank you!
1 mol Ag = 107.??. You need to look up the atomic mass to get an exact number. There are 6.022 x 10^23 atoms in this mass of Ag. so the conversion is either
6.022 x 10^23 atoms/1 mol OR
1 mol/6.022 x 10^23 atoms.
Convert 2.3 x 10^24 atoms to mols Ag using the appropriate factor above. Then convert mols Ag to grams silver using either of the following. I suspect you are to use dimensional analysis for this part, also, although you know mols x molar mass = grams.
107.?? g Ag/1 mol OR
1 mol/107.?? g Ag.
Post your work if you get stuck.
Not good
To solve this problem using dimensional analysis, we need to use the Avogadro's number and the molar mass of silver.
Avogadro's number states that 1 mole = 6.022 x 10^23 atoms. This means that if we have the number of atoms (2.3 x 10^24), we can determine the number of moles.
First, we need to convert from atoms to moles:
2.3 x 10^24 atoms * (1 mole / 6.022 x 10^23 atoms) = 3.821 moles
Next, we need to use the molar mass of silver, which is 107.87 g/mol.
Finally, we can convert from moles to grams using the molar mass:
3.821 moles * (107.87 g / 1 mole) = 412.64 grams
Therefore, there are 412.64 grams in 2.3 x 10^24 atoms of silver.
Should be 28.17grams
You divide 6x10^23 (particles in one mole) by 2.3x10^24
Then multiple that answer by the mass of one Ag mole which is 108g
This is the only way I know how to find the grams