Posted by Avonlea on Saturday, October 6, 2007 at 9:23pm.
Write the molecular equation.
CuCl2(aq) + 2NaOH(aq) ==> Cu(OH)2(s) + 2NaCl(aq)
Then the net ionic equation follows:
Cu^+2(aq) + 2Cl^-(aq) + 2Na^+(aq) + 2OH^-(aq) ==> Cu(OH)2(s) + 2Na^+(aq) + 2Cl^-(aq)
Now cancel the ions common to both sides; i.e., cancel 2Cl^- and 2Na^+ to leave
Cu^+2 (aq) + 2OH^-(aq) ==> Cu(OH)2(s)
Check my work closely.
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