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November 27, 2014

November 27, 2014

Posted by **Jane** on Saturday, October 6, 2007 at 11:13am.

[(x^2-49y^2)/(6x^2+42y)] / (x^2 - 7xy)

[(x^2-49y^2)/(6x^2+42y)]*[1/(x^2 - 7xy)]

{[(x+7y)(x-7y)]/6(x^2+7y)]}*[1/ x(x-7y)]

{[(x-7y)]/6(x^2+7y)]}*[1 / x]

(x+7y) / [6x(x^2+7y)]

- algebra -
**Reiny**, Saturday, October 6, 2007 at 11:35amAccording to your original line you are correct, but...

are you sure that the second bracket wasn't (6x^2+42xy) ?

Then I would have worked out better and the answer would have been 1/(6x^2)

- algebra -
**Jane**, Saturday, October 6, 2007 at 12:05pmnope I am positive it is the way I have it written. This problem has caused me more grief because I thought there should have been a "x" in it also. Thanks for looking at it for me.

- algebra -

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