Posted by **Lindsay** on Friday, October 5, 2007 at 1:25pm.

A stone is thrown vertically upward. On its way up it passes point A with speed v, and point B, 12.6 m higher than A, with speed v/2. Calculate the maximum height reached by the stone above point B.

What equation can I use to get the maximum height?

- Physics -
**bobpursley**, Friday, October 5, 2007 at 1:38pm
You can find the Kinetic energy at point B (1/2 mv2^2). That will equal the change in PE to the top (mgh)

set them equal, notice the mass divide out.

h= 1/2 (v2)^2 /g

The 12.6 meters, and v has nothing to do with the problem, it is not needed.

- Physics -
**Lindsay**, Friday, October 5, 2007 at 4:06pm
So, am I supposed to figure out v2?

And what is g, in this case?

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