Posted by **Lindsay** on Friday, October 5, 2007 at 1:25pm.

A stone is thrown vertically upward. On its way up it passes point A with speed v, and point B, 12.6 m higher than A, with speed v/2. Calculate the maximum height reached by the stone above point B.

What equation can I use to get the maximum height?

- Physics -
**bobpursley**, Friday, October 5, 2007 at 1:38pm
You can find the Kinetic energy at point B (1/2 mv2^2). That will equal the change in PE to the top (mgh)

set them equal, notice the mass divide out.

h= 1/2 (v2)^2 /g

The 12.6 meters, and v has nothing to do with the problem, it is not needed.

- Physics -
**Lindsay**, Friday, October 5, 2007 at 4:06pm
So, am I supposed to figure out v2?

And what is g, in this case?

## Answer This Question

## Related Questions

- physics - A stone is thrown vertically upward. On its way up it passes point A ...
- Physics 4a - A stone is thrown vertically upward. On its way up it passes point ...
- physics - A stone is thrown vertically upward. On its way up it passes point A ...
- Physics - A stone is thrown vertically upward. On its way up it passes point A ...
- Physics - A stone is thrown vertically upward. On its way up it passes point A ...
- physics - A stone is thrown vertically upward. On its way up it passes point A ...
- physics - A stone with mass m = 2.3 kg is thrown vertically upward into the air ...
- physics - A ball is thrown vertically upward with an initial speed of 20 m/s. ...
- physics - ll is thrown vertically upward with an initial speed of 16 m/s. Then, ...
- physics - ll is thrown vertically upward with an initial speed of 16 m/s. Then, ...

More Related Questions