Physics
posted by Lindsay on .
A stone is thrown vertically upward. On its way up it passes point A with speed v, and point B, 12.6 m higher than A, with speed v/2. Calculate the maximum height reached by the stone above point B.
What equation can I use to get the maximum height?

You can find the Kinetic energy at point B (1/2 mv2^2). That will equal the change in PE to the top (mgh)
set them equal, notice the mass divide out.
h= 1/2 (v2)^2 /g
The 12.6 meters, and v has nothing to do with the problem, it is not needed. 
So, am I supposed to figure out v2?
And what is g, in this case?