# math

posted by
**you** on
.

Find the general form of the equation of the circle.

Center at the point (-4,-3); containing the point (-3,3)

a) x^2+y^2+8x+6y-12=0

b) x^2+y^2+4x-6y+22=0

c) x^2+y^2-4x+6y+22=0

d) x^2+y^2+4x-6y+4=0