Friday

April 18, 2014

April 18, 2014

Posted by **Lindsay** on Thursday, October 4, 2007 at 3:47pm.

Do I need to know the velocity in order to solve this? I'm completely lost.

- Physics -
**Quidditch**, Thursday, October 4, 2007 at 4:31pmDetermine the velocity just as the ball makes first contact with the floor. Determine the velocity as the ball just just leaves the floor. Calculate the delta velocity. Divide this by the delta t to get (delta v)/((delta t) which is average acceleration. Look for the forumula relating velocity to acceleration and distance. It will look something like v=sqrt(2*?*?)

- Physics -
**Lindsay**, Thursday, October 4, 2007 at 4:40pmWhat information must I use to get the velocities?

- Physics -
**Anonymous**, Thursday, October 4, 2007 at 7:49pmVelocity= sqrt(2 * acceleration * distance). This is a special case where the velocity is zero at one end of the path which is the case here.

acceleration is gravity

the two distances are given. The signs of the two velocities are different. Remember that when you subtract them.

Then divide the difference by the delta time to get a m/(s^2) acceleration.

**Related Questions**

Physics - A golf ball released from a height of 1.80 m above a concrete floor, ...

physics - a golf ball released from a height of 1.5 m above aa concreate floor ...

physics - A 0.10 kilogram ball dropped vertically from a height of 1.0 meter ...

Physics - The Colliding Balls: A ball is released from rest at a height h above ...

Physics - if a ball is released from a certain height.The velocity-time graph ...

physics - A hard rubber ball, released at chest height, falls to the pavement ...

physics - a superball of mass .125 kg is dropped onto a concrete floor from a ...

Physics - A basketball player attempting a free throw shoots the ball at an ...

math - the height that a ball bounces varies directly as the height from which ...

physics - A ball dropped from a sixth floor window accelerates at 10 m/s After ...