Post a New Question

physics

posted by on .

A penny is dropped from the observation deck of the Empire State building (370 m above ground). With what velocity does it strike the ground? Ignore air resistance.

  • physics - ,

    distance = 1/2 gt^2 Solve for time it takes for the penny to reach the ground.
    Then distance = 1/2(Vinitial + Vfinal)t.
    Vinitial is zero. You know distance and t, solve for Vfinal.

  • physics - ,

    12

  • physics - ,

    85.2

  • physics - ,

    d=1/2gt^2
    t^2=2d/g
    t^2=2(370)/9.8
    t^2=75.51
    t=8.6 second

    v2=v1+gt
    v2=0+(9.8m/s^2)(8.6s)
    v2=84.3m/s

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question