A solution of potassium phosphate is mixed with a solution of calcium acetate.

I am supposed to write a net ionic equation. Doesn't need to be balanced.
Here is what I did:

K3PO4(aq) + Ca(C2H3O2)2 --> KC2H3O2 + Ca3PO4

3K+ + PO4-3 + Ca+2 2(C2H3O2-) --> K+ + C2H3O2 + 3Ca+2 + PO4-3

2K+ + Ca+2 + C2H3O2 --> 2Ca+2

K3PO4(aq) + Ca(C2H3O2)2 --> KC2H3O2(aq) + Ca3(PO4)2 See Ca3(PO4)2. See (aq) I inserted above.

3K+ + PO4-3 + Ca+2 + 2(C2H3O2-) --> K+ + C2H3O2 + 3Ca+2 + PO4-3
See the + sign I inserted above in bold. Then, Ca3(PO4)2 is the correct formula for calcium phosphate. Finally, Ca3(PO4)2 is insoluble and should be wirtten as a solid.

2K+ + Ca+2 + C2H3O2 --> 2Ca+2

To write a net ionic equation, you need to identify the ions that are involved in the chemical reaction and write their corresponding formulas.

In this case, potassium phosphate (K3PO4) will dissociate into three potassium ions (K+) and one phosphate ion (PO4³⁻). Calcium acetate (Ca(C2H3O2)2) will dissociate into one calcium ion (Ca²⁺) and two acetate ions (C2H3O2⁻).

The next step is to determine the products formed when the two solutions are mixed. In this case, potassium acetate (KC2H3O2) and calcium phosphate (Ca3PO4) are formed.

Combining these, the net ionic equation can be written as:

3K⁺ + PO4³⁻ + Ca²⁺ + 2(C2H3O2⁻) → 2Ca²⁺ + 2(C2H3O2⁻)

Therefore, the net ionic equation for the reaction between potassium phosphate and calcium acetate is:

3K⁺ + PO4³⁻ + Ca²⁺ + 2(C2H3O2⁻) → 2Ca²⁺ + 2(C2H3O2⁻)

Ok, thanks I had that written on the paper, but I forgot to type it. Also, descriptive subscripts are not required for this assignment so I didn't bother with them.

Thanks DrBob222!

net ionic equation is

PO4^-3(aq) + Ca^+2(aq) ==> Ca3(PO4)2(s)