Two books of masses m1=10kg and m2= 20kg are connected by a rope. The horizontal force on the more massive box is 900 N. Assume there's no friction.

a) what is the acceleration of the more massive box
b) Acclereration of the less massive box

a) f=ma
900=20a
a=45m/s^2
b) f=ma
900=10a
90m/s^2 =a
did i do this problem correct?

Yes, you solved the problem correctly.

a) To find the acceleration of the more massive box with a mass of 20 kg, you used Newton's second law, F = ma. Given that the force applied is 900 N, you correctly set up the equation as 900 = 20a and solved for the acceleration. The result is a = 45 m/s^2.

b) Similarly, to find the acceleration of the less massive box with a mass of 10 kg, you again used Newton's second law, F = ma. With the same applied force of 900 N, you set up the equation as 900 = 10a and solved for the acceleration. The result is a = 90 m/s^2.

Well done!

Yes, you have correctly solved the problem and obtained the correct accelerations for both boxes.

To calculate the acceleration of each box, you used Newton's second law: Force = mass x acceleration (F = ma).

For the more massive box with a mass of 20 kg:
F = 900 N
m = 20 kg
Using F = ma, we can rearrange the formula to solve for acceleration:
a = F/m
a = 900 N / 20 kg
a = 45 m/s^2

For the less massive box with a mass of 10 kg:
F = 900 N
m = 10 kg
Using F = ma:
a = F/m
a = 900 N / 10 kg
a = 90 m/s^2

Therefore, the acceleration of the more massive box is 45 m/s^2, while the acceleration of the less massive box is 90 m/s^2.