Tuesday

September 16, 2014

September 16, 2014

Posted by **Tammy** on Wednesday, October 3, 2007 at 2:05pm.

I think i would use F=ma and F=m_total*a

I chose 5N to be the applied force. so F=ma

5=m(3)

m=1.66

then F=m_total*a

5=(1.66+1)(2)

5=5.32

But this isn't valid. What am I doing wrong?

**Answer this Question**

**Related Questions**

physics - How many uniform, identical textbooks of width 25.0 cm can be stacked ...

Physics - I push a stack of six books (each weighting 4 kg) horizontally across ...

Physics 1 - There are six books in a stack, and each book weighs 5 N. The ...

Physics Help2I!!! - There are six books in a stack, and each book weighs 5N. ...

Physics - There are six books in a stack, and each book weighs 5 N. The ...

physics - please help There are six books in a stack, and each book weighs 5 N. ...

PreCal - You have 1000 coins. Start by placing one coin in its own "stack." Next...

Math - Need help on writing an equation. the question is let H represent the ...

physics - A person is standing on an object 10 ft high and his weight is 45 kg...

MATHEMATICS - A piece of notebook paper is about 0.0032 inch thick. If you begin...