how many 4 inch by 8 inch bricksare needed tobuild a walk 6 feet wide and 24 feet long?
divide the area of the walk by the surface area of the brick
Area walk= 24*6 ft^2
Area brick= (4/12)*(8/12) ft^2
6' wide x 12 in/ft = 72 inches
72 inches/4 inches/brick = 18 bricks needed for the 6 foot side.
24' long x 12 in/ft = 288 inches.
288 inches/8 inches/brick = 36 bricks needed for the 24 foot side.
18 bricks wide x 36 bricks long = ?? bricks total to cover the area.
To determine the number of 4-inch by 8-inch bricks needed to build the walkway, we first need to calculate the total area of the walkway.
First, convert the measurements from feet to inches:
Width: 6 feet = 6 * 12 = 72 inches
Length: 24 feet = 24 * 12 = 288 inches
Now, calculate the area of the walkway:
Area = Width * Length
Area = 72 inches * 288 inches
Area = 20,736 square inches
Since each brick measures 4 inches by 8 inches, the area covered by each brick is:
Brick Area = 4 inches * 8 inches
Brick Area = 32 square inches
Now, we can calculate the number of bricks needed by dividing the total area of the walkway by the area covered by each brick:
Number of Bricks = Total Area / Brick Area
Number of Bricks = 20,736 square inches / 32 square inches
Using division, we find that:
Number of Bricks = 648 bricks
Therefore, you would need 648 bricks measuring 4 inches by 8 inches to build a walkway that is 6 feet wide and 24 feet long.