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hey I am really stumped...I would really appreciate some help with this question

1.0560g of antacid is weighed and mixed with 75.00mL of excess 0.1126 M HCL. The excess acid required 4.68mL of 0.1008 M NaOH or back titration Calculate the neutalizing power of the antacid in terms of mmol H+ per gram of antacid

  • chem - ,

    Solve the excess acid first.

    MolesExcessAcid= moles NaOH
    VolumeExcess*MolariatyEx= .00468L*.1008

    solve for volume excess, then subtract it from the original volume, and you can then solve to antacid titration.

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