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February 1, 2015

February 1, 2015

Posted by **nicole** on Monday, October 1, 2007 at 9:30pm.

HOW IN THE HECK AM I SUPPOSED TO SET UP THIS EQUATION? PLEASE HELP... I AM DESPERATE!

- algebra 1 -
**Danielle**, Monday, October 1, 2007 at 9:32pmTry:

56 = n + 2/5n

- algebra 1 -
**nicole**, Monday, October 1, 2007 at 9:34pmThanks :) but now I'm stuck on actually finding out what the integers are :(

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- algebra 1 -
**DrBob222**, Monday, October 1, 2007 at 9:35pmWhat is your problem with solving the equation?

- algebra 1 -
**nicole**, Monday, October 1, 2007 at 9:38pmI just don't know how to go about it.

I have

n + 2/5n = 56

but now what?

- algebra 1 -
**DrBob222**, Monday, October 1, 2007 at 9:50pm

n + (2/5)n = 56

The simple way is to convert 2/5 to a decimal. You can divide 2 by 5 on your calculator and obtain 0.4, then

n + 0.4n = 56

1n + 0.4n = 56

1.4n = 56

divide both sides by 1.4

1.4n/1.4 = 56/1.4

n = ??

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- algebra 1 -
- algebra 1 -
**manny**, Monday, October 1, 2007 at 9:39pm56 = 1n +(2/5)n

56 = (1+(2/5))n

56 = (7/5)n

n = (5/7)*56

n= 40

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- algebra 1 -
**nicole**, Monday, October 1, 2007 at 9:41pmTHANK YOU SO MUCH! now it makes sense!!!!!!!!!!!!!!!!!!!!!!!!!

- algebra 1 -

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