1. I did it this way, but it doesn't check right
2(10-y)=30
_ _
2 2
(10-y)=15
+10 +10
y = 25
Check: 2 (10-15) = 30
-30 is not equal to 30!!!
You need to clarify. Use parenthese; I can't tell where the dividion takes place from your post.
Well y = to 15 right? 2(15-10)= 18?
To solve the equation 2(10-y) = 30, you attempted to first distribute the 2 to both terms in the parentheses, resulting in 20 - 2y = 30. Then, you isolated the variable term by subtracting 20 from both sides, giving you -2y = 10. Finally, you solved for y by dividing both sides by -2, yielding y = -5.
To check your solution, you substituted the value of y back into the original equation and found that 2(10 - 15) is not equal to 30. This discrepancy suggests that your solution might be incorrect. Therefore, let's go through the steps again to find the correct solution:
Starting with the equation 2(10-y) = 30:
1. Distribute the 2 to both terms inside the parentheses:
20 - 2y = 30
2. Isolate the variable term by subtracting 20 from both sides:
-2y = 10
3. Solve for y by dividing both sides by -2:
y = -5
Now, let's check this solution:
Substituting y = -5 back into the original equation:
2(10 - (-5)) = 30
2(10 + 5) = 30
2(15) = 30
30 = 30
Since both sides of the equation are equal, the solution is correct. It appears there was a mistake in your previous check where you evaluated 2(10-15), which should have been 2(10-(-5)) or 2(15).