# Algebra

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A homeowner wishes to insulate her attic with fiberglass insulation to
conserve energy. The insulation comes in 40-cm wide rolls that are cut to fit between
the rafters in the attic. If the roof is 6 m from peak to eave and the attic space
is 2 m high at the peak, how long does each of the pieces of insulation need to be?
Round to the nearest tenth.

• Algebra -

I am sorry, How would I set this problem up?

• Algebra -

First, you have a right-angle triangle; its height is 2 m and its hypotenuse is 6 m. To find the base, use the Pythagorean theorem: a^2 + b^2 = c^2. This gives you half the length of a piece of insulation. Double that number to find the total length of each piece.

If you post your answer, we'll be glad to check it.

• Algebra -

Okay,If I understand this is what I come up with.
square root of 6^2-2^2=x^2
square root of 36-4=x^2
square root of 32=x^2
x=4 square root of 2*2= x=8 square root of 2= approx. 11.3 m

• Algebra -

Right! You've got it! :-)

• Algebra -

Thanks! :)

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