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February 1, 2015

February 1, 2015

Posted by **Micha** on Monday, October 1, 2007 at 12:34pm.

conserve energy. The insulation comes in 40-cm wide rolls that are cut to fit between

the rafters in the attic. If the roof is 6 m from peak to eave and the attic space

is 2 m high at the peak, how long does each of the pieces of insulation need to be?

Round to the nearest tenth.

- Algebra -
**Micha**, Monday, October 1, 2007 at 12:34pmI am sorry, How would I set this problem up?

- Algebra -
**Ms. Sue**, Monday, October 1, 2007 at 1:15pmFirst, you have a right-angle triangle; its height is 2 m and its hypotenuse is 6 m. To find the base, use the Pythagorean theorem: a^2 + b^2 = c^2. This gives you half the length of a piece of insulation. Double that number to find the total length of each piece.

If you post your answer, we'll be glad to check it.

- Algebra -
**Micha**, Monday, October 1, 2007 at 2:04pmOkay,If I understand this is what I come up with.

square root of 6^2-2^2=x^2

square root of 36-4=x^2

square root of 32=x^2

x=4 square root of 2*2= x=8 square root of 2= approx. 11.3 m

- Algebra -
- Algebra -
**Ms. Sue**, Monday, October 1, 2007 at 2:44pmRight! You've got it! :-)

- Algebra -
**Micha**, Tuesday, October 2, 2007 at 12:33amThanks! :)

- Algebra -

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