Posted by Micha on Monday, October 1, 2007 at 12:35am.
what is the a~ all about? If it is a square root symbol then the solution looks like this:
x + (2x-5)^(1/2) = 10 : move x to other side
(2x-5)^(1/2) = 10 - x : square both sides
2x-5 = (10-x)^2 : expand the squared term
2x-5 = 100-10x-10x+x^2 : combine terms
0 = 105 - 22x + x^2 : use quadratic formula to solve for x
x =[-(-22) +/- sqrt(22^2 -4*1*105)]/(2*1)
x= [22 +/- sqrt(484 - 420)]/2
x= [22 +/- 8] / 2
x= 7 or 15
Plugging back into our initial equation shows that 7 is a solution, but 15 is not. This is because we started with a square root, which is invalid for negative numbers.
Regards.
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