Posted by Jacob on Sunday, September 30, 2007 at 4:28pm.
The slope of a straignt tangent line at any point of a y(x) curve is the derivative of the y(x) function at that point.
To get the derivative this way, you would have to draw a series of tangent lines at diffent points of the curve, measure the slope of each line, and replot the derivative function (slope vs. x) using those measured points.
Thank you very much, drwls.
I actually understand it now!
(You saved me in Calculus!) :-)
Related Questions
Calculus (Help) - The graph of y=cos x * ln cos^2x has seven horizontal tangent ...
Calculus (Help) - The graph of y=cos x * ln cos^2x has seven horizontal tangent ...
calculus - The function f is defined by f(x) = x^3 - x^2 - 4x + 4 The point (a,b...
cal - Equations of the tangent lines to hyperbola xy=1 that pass through point...
Calculus - Let f be a twice-differentiable function defined on the interval -1.2...
calculus - f(x)=kx^2+3 a) if the tangent lines to the graph of f at (t,f(t)) and...
Calculus - Find the equation of the line tangent to the graph of y=4 e^x at x=2...
Calculus c - Let f be a twice-differentiable function defined on the interval -1...
calc - The function f is defined by f(x) = x^3 - x^2 - 4x + 4 The point (a,b) is...
Calculus (Continuity and Differentiability) - Okay. So I am given a graph of a ...
For Further Reading
