Sunday
November 23, 2014

Homework Help: calculus

Posted by nick on Sunday, September 30, 2007 at 9:52am.

The function f is defined by
f(x) = x^3 - x^2 - 4x + 4

The point (a,b) is on the graph of f and the line tangent to the graph at (a,b) passes thru the point (0, -8) which is not on the graph of f. Find the values of a and b.

I have no clue how to solve this
I know the derivative of f prime (x) is
3x^2 - 2x - 4 and so (a,b) would be on the derivative line and so would (0, -8) but how do i find (a,b)???

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Calculus - 1. Given the function f defined by f(x) = x^3-x^2-4X+4 a. Find the ...
Calculus - Functions? - #1. A cubic polynomial function f is defined by f(x) = ...
Calculus - Given the function defined as f(x)=x^3-(3/2)x^2-6x+10 a) Explain why ...
Calculus - Given the function defined as f(x)=x^3-(3/2)x^2-6x+10 a) Explain why ...
Calculus - Let f be the function defined by f(x)=2x+11-3e^x If the equation of ...
Calculus - Find an equation of the tangent line to the graph of the function f ...
Calculus - Find an equation of the tangent line to the graph of the function f ...
CALCULUS HELP - Write the equation of the tangent line to the graph of the ...
Calculus 2nd Post please help - Find an equation of the tangent line to the ...
Calculus - Find the slope m of the tangent line to the graph of the function at ...

Search
Members