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March 6, 2015

March 6, 2015

Posted by **nick** on Sunday, September 30, 2007 at 9:52am.

f(x) = x^3 - x^2 - 4x + 4

The point (a,b) is on the graph of f and the line tangent to the graph at (a,b) passes thru the point (0, -8) which is not on the graph of f. Find the values of a and b.

I have no clue how to solve this

I know the derivative of f prime (x) is

3x^2 - 2x - 4 and so (a,b) would be on the derivative line and so would (0, -8) but how do i find (a,b)???

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