The summ of two numbers is two. THe difference between eight and twice the smaller number is two less than four times the larger. Find the two munbers.
find the value of the variable and ST if S is between R and T.
1.RS=7a, ST=12a,RS=28
2. RS=12,ST=2x,RT=34
3. RS=2x,ST=3x,RT=25
4. RS=16,ST=2x,RT=5x+10
5. RS=3y+1,ST=2y,RT=21
6. RS=4y-1,ST=2y-1,RT=5y
David, let x stand for smaller number and y for the larger. This gives you these two equations.
x + y = 2 or x = 2 - y
2x - 8 = 4y - 2
Substitute the value of x from the first equation into the second and solve.
I hope this helps. Thanks for asking.
Kaniz, if you have a question, it is much better to put it in as a separate post in <Post a New Question> rather than attaching it to a previous question, where is more likely to be overlooked.
I have no idea what ST, S, R and T indicate, so I cannot help you. Define your variables more clearly in another separate post, and we will try to help you. However, we will not do the work for you.
I hope this helps. Thanks for asking.
find the valueof the variable and ST if S is between R and T.
RS=7a, ST=12a, RS=28
To solve this problem, we can set up a system of two equations using the given information. Let's assume that the smaller number is represented by 'x' and the larger number is represented by 'y'.
From the statement, "The sum of two numbers is two", we can write the equation:
x + y = 2 --(Equation 1)
The second statement says "The difference between eight and twice the smaller number is two less than four times the larger." This can be written as:
8 - 2x = 4y - 2 --(Equation 2)
Now, we have a system of two equations with two unknowns. We can solve them simultaneously to find the values of 'x' and 'y'.
To solve this system, we can use the method of substitution or elimination. Let's use the method of elimination:
Multiply Equation 1 by 2:
2x + 2y = 4 --(Equation 3)
Now, subtract Equation 2 from Equation 3 (eliminating the 'x' term):
(2x + 2y) - (8 - 2x) = 4y - 2 - (4y - 2)
Simplifying the equation:
2x + 2y - 8 + 2x = 4y - 2 - 4y + 2
4x + 2y - 8 = 0
Rearranging the equation:
4x + 2y = 8 --(Equation 4)
Now we have two equations:
4x + 2y = 8 --(Equation 4)
x + y = 2 --(Equation 1)
To eliminate 'y', we'll multiply Equation 1 by 2:
2(x + y) = 2(2)
2x + 2y = 4
We can see that Equation 4 and the modified Equation 1 are the same. This means that the system of equations has infinitely many solutions, and any values of 'x' and 'y' that satisfy one of the equations will also satisfy the other.
Therefore, we cannot determine a unique solution for this problem.