# Intermediate Algebra

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Combine like terms:
-3x^2+2x-4x^2-9+6x-2x^2+8

Solve for x:
8x-11= -11x+18

Solve for x:
-2(x-5)+7=z-8-5x

Solve for x:
(x-2)/5 - 3/2= (x+1)/10

Translate to an algebra statement; do not solve:
Seven times the difference of six and a twice a number yields the same result as the same number decreased by one.

• Intermediate Algebra -

I will be happy to critique your work. To solve for x, combine the terms that include x on one side and the constants on the other.

"Combining" like terms" means separately combining the terms with different powers of x, and the constants.

• Intermediate Algebra -

Seven times the difference of six and a twice a number yields the same result as the same number decreased by one.

How does this translate into a algebra statement?

• Intermediate Algebra -

7(6-x2) = x2-1

• Intermediate Algebra -

first you want to combined all the squared problems whch is : 3x^2 -4x^2-2x^2
Since two negatives make a positive : 3x^2-4x^2 =7x^2
now subtract -2x^2 and that leaves for 5x^2

Now you combine all the numbers with variables : 2x +6x = 8x
so now we have
5x^2+ 8x

now we combine all the constant numbers -9+8= -1

• Intermediate Algebra -

Seven times the difference of six and a twice a number yields the same result as the same number decreased by one.

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• Intermediate Algebra -

The ratio of 7 more than a number to 2 less than that number is 13/4. Find the number