Posted by Dawn on Saturday, September 29, 2007 at 10:42pm.
I will be happy to critique your work. To solve for x, combine the terms that include x on one side and the constants on the other.
"Combining" like terms" means separately combining the terms with different powers of x, and the constants.
Seven times the difference of six and a twice a number yields the same result as the same number decreased by one.
How does this translate into a algebra statement?
7(6-x2) = x2-1
I can answer 3x^2+2x-4x^2-9+6x-2x^2+8
first you want to combined all the squared problems whch is : 3x^2 -4x^2-2x^2
Since two negatives make a positive : 3x^2-4x^2 =7x^2
now subtract -2x^2 and that leaves for 5x^2
Now you combine all the numbers with variables : 2x +6x = 8x
so now we have
5x^2+ 8x
now we combine all the constant numbers -9+8= -1
answer 5x^2+8x -1
Seven times the difference of six and a twice a number yields the same result as the same number decreased by one.
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