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The electrons in the beam of a television tube have a kinetic energy of 2.10 10-15 J. Initially, the electrons move horizontally from west to east. The vertical component of the earth's magnetic field points down, toward the surface of the earth, and has a magnitude of 5.00 10-5 T.

(a) In what direction are the electrons deflected by this field component?

due south (correct)
due west
due east
due north

(b) What is the acceleration of an electron in part (a)?

Force = q V X B
where V and B are vectors and "x" denotes the vector "cross product". For an electron, q is negative. In (a), V is towards the east (unit vector i) and B is down (unit vector -k). The vector V x B is north (according to he right hand rule) and the minus sign of q makes the force to the south.

(b) The acceleration is F/m, in the same direction as the force F. m is the mass of the electron

I am so confused! Can you please define "cross product". I interpret it to mean that you multiply the value of V and B. Obviously this is incorrect.

Will my answer have a negative value because of the mass of the electron?

This is what I did:

Acceleration = [(q V X B)/ m
(-1.60x10^-19)(6.789932x10^12)(X)(5.00x10^-5)] / 9.11x10^-31)

I got the value of V from the equation for KE

KE = 1/2m V^2

2.10x10^-5 J = 1/2(9.11x10^-31)V^2

(2.10x10^-5)/(4.555x10^-31) = V^2

4.610318x10^25 = V^2

6.789932x10^12 = V

Your answer for the magnitude of the acceleration will not have a negative sign. However, you must specify the direction.

You should be familiar with the term "cross prodct" if you are studying the forces of magnetic fields. It is a vector concept and vectors are usually tught in introductory calculus and analytic geometry. Awhat a cross product A X B means is |A|*|B| sin theta, where |A| amd |B| are the magnitudes of two vectors and theta is the angle between them. The direction of A X B is perpendicular to the plane containing A and B