Posted by **Sarah** on Friday, September 28, 2007 at 11:11pm.

A kayaker paddled 2 hours with a 6 mph current in a river. The return trip against the same current took 3 hours. Find the speed the kayaker would make in still water.

- Math -
**DrBob222**, Friday, September 28, 2007 at 11:29pm
Let x = kayaker paddle speed.

Then going down the river his speed is 6+x and since distance = rate*time then distance = (6+x)*2 hrs or d = 12 + 2x.

On the return trip his speed is 6-x and the distance is (6-x)*3 hrs or d = 18-3x

The two distances are equal; therefore, set the two equations equal and solve for x. Check my thinking. Check my work.

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