Thursday
July 31, 2014

Homework Help: physics

Posted by Anonymous on Wednesday, September 26, 2007 at 8:55pm.

A student stands at the edge of a cliff and throws a stone horizontally over the edge with a speed of 18m/s. The cliff is 50m above a flat horizontal beach, as shown in Figure 3.20. How long after being released does the stone strike the beach below the cliff? With what speed and angle of impact does it land?

Work:

-50m=-1/2(9.8m/s^2)t^2
t=3.19s

x=(18m/s)(3.19s)=57.4m
vy=0-(9.8m/s^2)(3.19s)=-31.3m/s

Am I doing everything correctly? How do I find the angle of impact?

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