The attendance at a baseball game was 400 people. Student tickets cost $2 and adult tickets cost $3. ( Man those are some cheap tickets.) Total ticket sales were $1050. How many tickets of each type were sold?

DIRECTIONS- Write an equation to model this situation.

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This was assigned for homework, and I DO NOT GET IT. AT ALL.

Plz help. Plz.

Let s - # of student tickets.

Let a = # of adult tickets.
s + a = 400
2s + 3a = 1050
Double the first equation
2s + 2a = 800
Subtract that from the second equation
a = 250

Use either of the first two equations to solve for s.

THANK YOU.

Sure! I'd be happy to help you with this problem. Let's break it down step by step.

First, let's define our variables:
Let's say the number of student tickets sold is S.
Let's say the number of adult tickets sold is A.

According to the problem, the attendance at the baseball game was 400 people. This means the total number of tickets sold (student tickets + adult tickets) would also be 400. So the first equation we can write is:

S + A = 400

Next, let's look at the ticket prices. Student tickets cost $2 and adult tickets cost $3. The total ticket sales were $1050. This means the revenue from the student tickets (2*S) plus the revenue from the adult tickets (3*A) should equal $1050. So our second equation is:

2S + 3A = 1050

So now we have two equations:
S + A = 400
2S + 3A = 1050

These two equations can be solved simultaneously to find the values of S and A, which represent the number of student and adult tickets sold, respectively. There are multiple methods to solve a system of equations, such as substitution, elimination, or graphing.

I hope this explanation helps! Let me know if you have any further questions.