mathalgebra
posted by Anonymous on .
15. Solve the following system of equations.
x + y – z = 1
x + y + z = 3
3x – 2y – z = 4:
A. (1, 3, 3)
B. (0, 1, 2)
C. (1, 0, 2)
D. (3, 1, 2)

Since this is multiple choice, why not just try which of the three sets of numbers satisfy all equations? Obviously, answer A does not satisfy x+y+z=3
Alternatively, use standard methods of algebra two reduce the number of vaiables to one, or use determinants.
I will be happy to critique your work.