Posted by **Anonymous** on Wednesday, September 26, 2007 at 12:59am.

7. A bag contains 5 red marbles, 6 green marbles, and 9 blue marbles. Suppose 3 marbles are chosen without replacement. What is the probability of choosing a red, a blue, and a red in that order?:

A. 9/320

B. 5/152

C. 1/1280

D. 1/38

Please explain answer. Thanks

- math-algebra -
**PsyDAG**, Wednesday, September 26, 2007 at 12:39pm
Find the probability of picking one of the colors. Since there is no replacement, the probability for the second would have a divisor of n-1 and the third would have n-2. The probability of all events occurring is found by multiplying the probabilities ofthe individual events.

I hope this helps. Thanks for asking.

## Answer this Question

## Related Questions

- math-algebra - 7. A bag contains 5 red marbles, 6 green marbles, and 9 blue ...
- math - sally has a bag with red,blue, and green marbles. She has twice as many ...
- probability - George has a bag of marbles. Inside the bag are 5 red marbles, 3 ...
- algebra2/ Trigonometry - A bag contains 24 green marbles, 22 blue marbles, 14 ...
- probability - A bag contains 3 red marbles, 3 blue marbles and 3 yellow marbles...
- Probability? - A bag contains 7 green marbles, 9 red marbles, 10 orange marbles...
- math - George has a bag of marbles. Inside the bag are 5 red marbles, 3 green ...
- math - George has a bag of marbles. Inside the bag are 5 red marbles, 3 green ...
- Math - Can someone please explain how to solve this problem? A bag contains 6 ...
- math - You draw 2 marbles from a bag containing 3 blue marbles, 2 green marbles...

More Related Questions