Posted by Anonymous on Wednesday, September 26, 2007 at 12:59am.
7. A bag contains 5 red marbles, 6 green marbles, and 9 blue marbles. Suppose 3 marbles are chosen without replacement. What is the probability of choosing a red, a blue, and a red in that order?:
A. 9/320
B. 5/152
C. 1/1280
D. 1/38

mathalgebra  PsyDAG, Wednesday, September 26, 2007 at 12:43pm
Please only post your questions once. Repeating posts will not get a quicker response. In addition, it wastes our time looking over reposts that have already been answered in a another post. Thank you.

mathalgebra  Fred, Thursday, December 8, 2011 at 9:24am
This answer was scored wrong, but I do not know why. If someone would kindly show me the error, I would appreciate it.
First choice probability: 5/20
Second choice probability: 6/19
Third choice probability: 9/18
Total Probability: (5/20)(5/19(9/18)=3/76
This answer is not featured above but the math seems correct. Each successive choice has fewer balls remaining, and the correct number of the desired balls for the next choice still remains in the bag for all the choices. The total probability is the product of the probability of each choice.

mathalgebra  Anonymous, Tuesday, February 21, 2012 at 12:19am
(¡) 5/17

mathalgebra  Cesar, Friday, February 24, 2012 at 12:59am
the answer is B. when you multiply you get (225/6840) simplifing this and you will get 5/152.

mathalgebra  james, Thursday, March 8, 2012 at 10:08pm
A cup contains 9 red jelly beans, 8 green jelly beans, and 8 blue jelly beans.
If a jelly bean is randomly chosen, what is the probability that it is not green? Write your answer as a simplified fraction.

mathalgebra  Anonymous, Saturday, October 6, 2012 at 3:25pm
17/25

mathalgebra  Andrew, Tuesday, May 27, 2014 at 4:00pm
the answer Red then blue the red is D.
1 of 38 or 2.63% chance
5 red chances /20 balls *
9 blue /19 * 4 red balls left /18
= .25 X .47368 * .2222 = .0263
or 1/38

mathalgebra  Anonymous, Tuesday, June 24, 2014 at 9:38pm
A bucket contains 5 yellow and 7 red balls. If 2 balls are selected randomly without replacement, what is the probability that they will both be yellow?

mathalgebra  Marty Murray, Sunday, July 6, 2014 at 10:05am
5/20*9/19*4/18 = 1/4*9/19*2/9 =
1/2*1/19 = 1/38
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