Saturday

February 28, 2015

February 28, 2015

Posted by **ND** on Wednesday, September 26, 2007 at 12:35am.

A. 100m x 50m

B. 75m by 75m

C. 150m x 150m

D. no solution

Please explain answer. Thanks!

- Math -
**drwls**, Wednesday, September 26, 2007 at 1:44amLet the unknown dimensions be a and b. Solve the two equations

a b = 5000

2a + 2b = 300

Simplify to a + b = 150 and substitute 150-a for b in the first equation.

a(150-a) = 5000

a^2 - 150 a + 5000 = 0

You could either solve by factoring or just see which of the multiple choices satsifies the two equations. There IS a solution.

**Answer this Question**

**Related Questions**

math - a rectangular field is to be enclosed with 600m of fencing. Find the ...

Calculus - A rectangular field is to be enclosed by a fence and divided into ...

Algebra 2 - A rectangular field is to be enclosed by 300 feet of fencing. Find ...

math - A rectangular field is to be enclosed by a fence. Two fences parallel to ...

algebra - The length of a rectangular field is 18 m longer than the width. The ...

Algebra - How to find dimensions of a field when given length of fencing and ...

Math - a rectangular field with an area of 8000 m^2 is enclosed by 400 m of ...

math - A total of 800m of fencing material is used to enclose a rectangular ...

math - the length of a rectangular field is 18 m longer than the width. the ...

MATH - A rectangular field is to be enclosed with 1200 ft of fencing. If the ...