Posted by **Lindsay** on Tuesday, September 25, 2007 at 6:17pm.

A robot probe drops a camera off the rim of a 239 m high cliff on Mars, where the free-fall acceleration is -3.7 m/s^2.

a) Find the velocity with which the camera hits the ground.

b) Find the time required for it to hit the ground.

Ok so I'm not even sure of which equation to use for this problem. Maybe if someone just gave me a hint as to where to begin, I could get the rest...?

- Physics -
**bobpursley**, Tuesday, September 25, 2007 at 6:24pm
vfinal^2 = vinitial62 + 2 a * height

solve for vfinal

vfinal= vinitial + a*t

solve for time.

Memorize these equations.

- Physics -
**Lindsay**, Tuesday, September 25, 2007 at 6:50pm
Ok so I plugged in the numbers and got 42.1 for a) and -11.4 for b).

However, my book says that I got them switched...that 11.4 s is a) and -42.1 m/s is b). How did this happen?

- Physics -
**Lily**, Sunday, October 4, 2015 at 12:16am
The post is 8 years old now, but for anyone viewing the page: The book is wrong because the unit for velocity is m/s, not s(seconds). Your answers are correct, Lindsay.

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