Posted by **JIM** on Monday, September 24, 2007 at 10:50pm.

You commute 56 miles one way to work. The trip to work takes 10 minutes longer than the trip home. Your average speed on the trip home is 8 miles per hour faster. What is your average speed on the trip home?

I got to this point

xy=56

(x-8)(y+10)=56

I couldn't get any further than that. I'm not sure where to go with those equations.

- Algebra -
**bobpursley**, Monday, September 24, 2007 at 11:04pm
Ok, then x=56/y

(56/y -8)*(y+10/60)=56

multiply both sides by y.

y(56/y -8)*(y+10/60)=56y

(56 -8y)*(y+10/60)=56y

FOIL that, and solve the quadratic for y. ONce you get that, you can solve for x.

Note:

The fraction 10/60 is important..the ten was in minutes, and it has to be converted to hours, as speed was given in km/hr (remember the units given for 8).

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