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October 25, 2014

October 25, 2014

Posted by **JohnX** on Monday, September 24, 2007 at 9:59pm.

a) if the boat heads directly for the opposite shore, how long will the trip take?

b)Where will the boat arrive on the opposite shore?

c)If the boat is to reach a point directly across from the starting point , in which direction should the boat head?

d)How long will the crossing take in case c)?

- Physics -
**bobpursley**, Monday, September 24, 2007 at 10:30pmIt will take 1.5/15 hr to get across

IT does downstream 5*1.5/15 km

For the c), draw the triangle. On side is 5km/hr, the hypotenuse is 15km/hr. Solve for the side going straight across, that is the velocity across. For the angle, SinTheta=5/15

- Physics -
**johnX**, Monday, September 24, 2007 at 11:16pmi didnt get the answer of bob very well. can he help me more widely.

the question is

Q)A boat moving at 15 km/h relative to water is crossing a river 1.5 km wide. The river flows at 5.0 km/h

a) if the boat heads directly for the opposite shore, how long will the trip take?

b)Where will the boat arrive on the opposite shore?

c)If the boat is to reach a point directly across from the starting point , in which direction should the boat head?

d)How long will the crossing take in case c)?

- Physics -
- Physics -
**Anonymous**, Friday, January 21, 2011 at 7:29pmuse this, Vx = dx * t

then use that t and find

Vy = dy * t

x and y are x dimension n y dimension

uhh..

i'll just do it,

Vx= 15 km/hr

dx = 1.5 km

dy = 5 km/hr

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