Post a New Question


posted by .

calculate the wavelength of the second line in the Brackett series (nf=4) of the hydrogen emission spectrum. Rh= 2.180e-18

any help please? i know its energy levels 4 to 6... but that is all.

  • Chemistry -

    1/lambda= R (1/4^2-1/662) R= Rydberg constant = (1.09678E7 m^-1)

    A little algebra changes this to

    1/lambda= R (36-16)/(16*36)

    solve for lambda.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question