calculate the wavelength of the second line in the Brackett series (nf=4) of the hydrogen emission spectrum. Rh= 2.180e-18
any help please? i know its energy levels 4 to 6... but that is all.
Chemistry - bobpursley, Monday, September 24, 2007 at 4:03pm
1/lambda= R (1/4^2-1/662) R= Rydberg constant = (1.09678E7 m^-1)
A little algebra changes this to
1/lambda= R (36-16)/(16*36)
solve for lambda.