ok i have another question..

in the square qrst and line qt is congruent to line ts and line rs is congruent to line ts, what is x? line qt=1/2(14x+8) and line rs= 6x+8 what is x?

qt and rs are equal-length sides of the square. Therefore

7x+ 4 = 6x = 8
That requires that x = 4

Which of the following prove line QR and line TS are parallel?

To solve for x, we can start by equating the lengths of line qt and line rs to line ts:

qt = ts (given)
1/2(14x + 8) = 6x + 8

Now, we can solve for x by simplifying and solving the equation step by step.

1. Distribute the 1/2 to 14x + 8:
(1/2) * 14x + (1/2) * 8 = 6x + 8
7x + 4 = 6x + 8

2. Subtract 6x from both sides of the equation:
7x - 6x + 4 = 6x - 6x + 8
x + 4 = 8

3. Subtract 4 from both sides of the equation:
x + 4 - 4 = 8 - 4
x = 4

Therefore, the value of x is 4.