express (x-7)(x+3) as a trinomal
Use the usual rules for multiplication
(x + a)(x + b) = x^2 + (a+b)x + ab
I think it is x2-4x-21
(x-7)(x+3)
To express (x-7)(x+3) as a trinomial, we need to multiply the two binomials together.
First, use the distributive property to multiply x by both terms inside the second parentheses and -7 by both terms inside the first parentheses:
(x * x) + (x * 3) + (-7 * x) + (-7 * 3)
Next, simplify each term:
x^2 + 3x - 7x - 21
Combine like terms:
x^2 - 4x - 21
So, the expression (x-7)(x+3) can be written as a trinomial: x^2 - 4x - 21.