Posted by anonymous on Saturday, September 22, 2007 at 3:07am.
1. Treat y = sqrt x as the variable ans solve for y. Then factor or use the quadratic equation.
3y^2 + 5y -28 = 0
(3y -7)(y +4) = 0
y = -4 x = +/- 2i are two of the answers. You do the other two.
2. let y^2 = x-2
2x - 5 = 2y^2-1
sqrt (2y^2 -1) = 2 + y
2y^2 -1 = y^2 +4y +4
y^2 -4y -5 = 0
(y-5)(y+1) = 0
y = 5 or -1
Now solve for x
3. Require that b^2 - 4ac > 0
(b = 5 and c = 2).
Solve the inequality for a
Related Questions
Math - I need help with these three problems. They are on a Study Guide and I ...
math - I need help with these three problems. They are on a Study Guide and I ...
Math - I need help with these three problems. They are on a Study Guide and I ...
Pre Algebra - Please help me with some problems. Thank you! Solve the equation ...
Math - Solve each equation by completing the square. -36x=8x^2+28 -8x^2-3x=-5 5x...
Math - Solve each equation by completing the square. -36x=8x^2+28 -8x^2-3x=-5 ...
math - 1. solve by using the quadratic formula. 5x^2+x=3 2. solve by completing ...
algebra - Can someone please help me with this one? Solve (5x+4)^1/2-3x=0 Just ...
Math Help - This is a substitution equation. Would that change the steps that ...
Pre-algebra - Could someone please help me solve the following problems, and ...
For Further Reading
