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1. [12/(x^2 - 4)] - [(3-x)/(x^2+2x)]
The answer is:
[(x^2 + 7x + 6)/x(x+z)(x-z)
I don't understand how to get that! was the z a typo? even if it's supposed to be a 2 - I don't understand!

  • math -

    yes, the z is a typo
    Factor 1/(x+2) out of each term and see what you get.
    [1/(x+2)][12/(x-2) - (3-x)/x]
    =[1/(x+2)][12x/x(x-2) - (3-x)(x-2)/x(x-2)]
    ={1/[(x-2)(x+2)]}[12x/x -(3-x)(x-2)/x]
    ={1/[(x-2)(x+2)]}[(x^2+ 7x +6)/x]
    That is in the form of your answer (except for the typo "z" for 2), but it can be factored further.
    = (x+6)(x+1)/[x(x-2)(x+2)]

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