For the following reaction, 0.506 moles of ammonia are mixed with 0.458 moles
of oxygen gas.
ammonia (g) + oxygen (g) nitrogen monoxide (g) + water (g)
What is the FORMULA for the limiting reagent?
What is the maximum amount of nitrogen monoxide that can be produced? moles
Balance the equation. Determine from the coefficents the mole ratio.
Given .506moles of NH3, how many moles of O2 do you need? Do you have that much, or more? If you do not have that much, then O2 is limiting, otherwise, you have an excess of O2 and NH3 is limiting.
I will be happy to critique your work.
To determine the limiting reagent and the maximum amount of product that can be formed, we need to compare the moles of each reactant to the stoichiometry of the balanced equation.
Step 1: Write the balanced equation:
ammonia (g) + oxygen (g) → nitrogen monoxide (g) + water (g)
Step 2: Calculate the moles of product that can be formed from each reactant:
Using the stoichiometry of the balanced equation, we know that the ratio of ammonia to nitrogen monoxide is 1:1, and the ratio of oxygen to nitrogen monoxide is 1:2.
For ammonia:
0.506 moles of ammonia x (1 mole of nitrogen monoxide / 1 mole of ammonia) = 0.506 moles of nitrogen monoxide.
For oxygen:
0.458 moles of oxygen x (2 moles of nitrogen monoxide / 1 mole of oxygen) = 0.916 moles of nitrogen monoxide.
Step 3: Compare the moles of product formed for each reactant:
The reactant that produces the smallest amount of product is the limiting reagent.
For ammonia: 0.506 moles of nitrogen monoxide
For oxygen: 0.916 moles of nitrogen monoxide
Since 0.506 moles of nitrogen monoxide is less than 0.916 moles of nitrogen monoxide, ammonia is the limiting reagent.
Therefore, the formula for the limiting reagent is ammonia (NH3).
Step 4: Calculate the maximum amount of product:
The maximum amount of nitrogen monoxide that can be produced is determined by the stoichiometry of the limiting reagent.
From the balanced equation, we know that the ratio of ammonia to nitrogen monoxide is 1:1.
Therefore, the maximum amount of nitrogen monoxide that can be produced is 0.506 moles.