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March 29, 2015

March 29, 2015

Posted by **anonymous** on Thursday, September 20, 2007 at 11:54pm.

I have the solutions but I don't understand how to get them!

1. Perform the indicated operations and simplify:

[(2/x)-1]/(x^2 -4)

2. Subtract and simplify:

[12/(x^2 -4)] - [(3-x)/(x^2 + 2x)]

3. Perform the indicated operations and simplify:

[(x/y)-(y/x)]^-1

4. Divide and simplify:

[(a^2 b)/(a-b)]/[(a+b)/(a^2-b^2)]

5. Perform the indicated operations and simplify

[(x/x-3)-(2x/x^2-2X-3)]/[(2/x+1)-(1/x)

Solutions:

1. -1/(x^2 + 2x)

2. [x^2 + 7x + 6]/[x(x+z)(x-z)]

--typo in book?

3. xy/(x^2 - y^2)

4. a^2 b

5. x^2/(x-3)

- math- please help! -
**drwls**, Friday, September 21, 2007 at 1:40am1. Rewrite (2/x) -1 in the numerator as -(x-2)/x

Factor (x^2/4) in the denominator as (x-2)(x+2)

Then cancel out the (x-2) terms in numerator and denominator. You wil be left with -1/[x(x+2)]

3. Rewrite x/y and y/x with a common denominator, xy.

[(x^2- y^2)/xy]^-1 = xy/(x^2- y^2)

You try the others. They are all exercises in factoring and canceling tems

- math- please help! -
**hhhhhhhhhhhh**, Thursday, November 8, 2012 at 9:36am8/9a^2 divide 4a^2-4a-24/a^2-6a+9 Perform the indicated operation

- math- please help! -
**Modest**, Saturday, February 2, 2013 at 1:02pm(2/3-1/6)divide by(1/4+4/5) reduce to lowes terms

- math- please help! -
**Anonymous**, Friday, February 6, 2015 at 10:35amidk edsgfjhdsh

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