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February 26, 2015

February 26, 2015

Posted by **Kay** on Thursday, September 20, 2007 at 12:47am.

1. sin0(cot0 + tan0) = sec0

2. cos0 +1/cos0 -1 = 1 + sec0/1 - sec0

- Trig -
**drwls**, Thursday, September 20, 2007 at 2:19am1. sin x (cot x + tan x) =

sin x (cos x/sin x + sin x/cos x) =

cos x + (sin^2/cos x) =

[cos^2 x + sin^2 x]/cos x =

1/cos x

= sec x

You try the other one

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