Posted by **Anonymous** on Wednesday, September 19, 2007 at 5:40pm.

A 56 kg swimmer jumps off a 15 m tower. Find the swimmer's velocity when hitting the water. The swimmer comes to a stop 2 m below the surface. Find the net force exerted by the water.

- Physics -
**Natalie**, Sunday, October 14, 2012 at 9:20pm
In the air:

Vi=0, d=15m, a=9.8m/s^2, vf=?

vf^2=vi^2+2ad

vf^2=0^2+2*9.8*15

vf=17.15m/s --> speed when hitting the water

Now for the water part:

vi=17.15m/s, vf=0,d=2,a=?

vf^2=vi^2+2ad

0^2=17.15^2+2*a*2

a=-73.5 m/s^2

F=ma

F=56*73.5=4116 N

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