Posted by **apoorva** on Tuesday, September 18, 2007 at 5:11pm.

t(min)x-value:36,38,40,42,44

heartbeats-y value: 2530, 2661, 2806,2948,3080

Graph these points(Each point goes with another so (36,2530), (38,2661)...

The monitor estimates this value by calculating the slope of a secant line. Use the data to estimate the heart rate after 42 minutes using the secant line between the points with the given values of t.

they give me t=36 and t=42 for the first problem:

First I found the slope between both points which i got 69.67.

then after i convert it to y=mx+b form. Then do i plug in 42 for x to find the heart rate.

Is that the right steps or no?

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