Posted by **apoorva** on Tuesday, September 18, 2007 at 5:11pm.

t(min)x-value:36,38,40,42,44

heartbeats-y value: 2530, 2661, 2806,2948,3080

Graph these points(Each point goes with another so (36,2530), (38,2661)...

The monitor estimates this value by calculating the slope of a secant line. Use the data to estimate the heart rate after 42 minutes using the secant line between the points with the given values of t.

they give me t=36 and t=42 for the first problem:

First I found the slope between both points which i got 69.67.

then after i convert it to y=mx+b form. Then do i plug in 42 for x to find the heart rate.

Is that the right steps or no?

## Answer This Question

## Related Questions

- Math (Calculus) (mean value theorem emergency) - Consider the graph of the ...
- Calculus - Graph the function f(x)=x+4/x Graph the secant line that passes ...
- calculus - Hi, I am lost on couple of problems and i was wondering if you could ...
- physics - I'm making a graph of force vs stretch for springs. I have 7 data ...
- math-repost - Data regarding the value of a particular color copier is ...
- Math (Secant Lines) - Consider the function f(x)=sqrt(x) and the point P(4,2) on...
- calculus 1 - The point P(2,-1) lies on the curve y=1/(1-x) If Q is the point (x...
- Calculus - The present value of a building in the downtown area is given by the ...
- Calculus - The present value of a building in the downtown area is given by the ...
- Calculus - The present value of a building in the downtown area is given by the ...

More Related Questions