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July 29, 2014

July 29, 2014

Posted by **Need Help** on Monday, September 17, 2007 at 9:01pm.

3x^2 - 4x + 1

PLEASE SHOW STEP BY STEP!!!

- Math -
**drwls**, Tuesday, September 18, 2007 at 8:55amAssume

3x^2 - 4x + C to be a perfect square, (ax + b)^2, where a abd b are constants. The square would be

a^2 + 2ab + b^2. Therefore

a = sqrt3 and 2b sqrt3 = -4

b = -2/sqrt 3

b^2 = 4/3

3x^2 - 4x + 1 = (x sqrt 3 - 2/sqrt3)^2 -1/3

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