Posted by **Soly** on Sunday, September 16, 2007 at 9:17pm.

Could you please check my work?

2. A 2 kg ball of putty moving to the right at 3m/s has a head-on inelastic collision with a 1 kg ball of putty moving to the left at 3m/s. What is the final magnitude and direction of the velocity of the stuck together balls after the collision?

m1v1 +m2v2= (m1+m2)u2

(2kg)(3m/s) + (1kg)(3/s)= (2kg +1kg)u2

6kg/m/s +3kg/m/s= (3kg)u2

9kg/m/s= (3kg)u2

9kg/m/s divided by (3kg)= 3m/s and the direction would be to the left

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