May i pls have some help balancing this equation
Al + NH4ClO4 ---> Al2O3 + AlCl3 + NO + H20
Thanks,
manny
Sorry i don't think my brain's working today.
Are the coeeficients
3,3,1,1,3,6
????
3,3>>1,1,3,6
Yeah. That what i meant
thanks!!
Sure, I can help you balance the equation:
To balance chemical equations, we need to ensure that the number of atoms of each element is equal on both sides of the equation.
Let's start by counting the number of each type of atom on each side of the equation:
On the left side (reactants):
- Al: 1 atom
- N: 1 atom
- H: 4 atoms
- Cl: 1 atom
- O: 4 atoms
On the right side (products):
- Al: 2 atoms
- O: 3 atoms
- Cl: 3 atoms
- N: 1 atom
- H: 1 atom
Now, let's try balancing the equation:
Al + NH4ClO4 ---> Al2O3 + AlCl3 + NO + H2O
First, let's balance the aluminum (Al) atoms. To equalize the number of Al atoms, we need to have a coefficient of 2 in front of Al on the reactant side:
2Al + NH4ClO4 ---> Al2O3 + AlCl3 + NO + H2O
Next, let's balance the hydrogen (H) and oxygen (O) atoms. We can start with oxygen:
2Al + NH4ClO4 ---> Al2O3 + AlCl3 + NO + H2O
There are now 3 oxygen atoms on the right side. To match that, we need to have a coefficient of 3 in front of H2O:
2Al + NH4ClO4 ---> Al2O3 + AlCl3 + NO + 3H2O
Now let's balance the hydrogen atoms. We have 8 hydrogen atoms on the right side (3H2O x 2 H atoms per water molecule). To balance this, we will need a coefficient of 8 in front of NH4ClO4:
2Al + 8NH4ClO4 ---> Al2O3 + AlCl3 + NO + 3H2O
Finally, let's balance the chlorine (Cl) and nitrogen (N) atoms. We have 12 Cl atoms on the right side (4 AlCl3 x 3 Cl atoms per molecule) and 8 N atoms on the left side. To balance this, we need a coefficient of 6 in front of NH4ClO4:
2Al + 8NH4ClO4 ---> Al2O3 + 2AlCl3 + NO + 3H2O
Now the equation is balanced, with the same number of atoms on both sides.