Homework Help: Beginning Alegbra

Posted by Nicole-Marie on Saturday, September 15, 2007 at 11:48pm.

We had a substitute in math on friday and we got a worksheet, but he didn't explain how to do it very well. Could someone work out a problem for me?

1. (2b^3)^3 * 3(b^-4)^2 =

I have no clue how to do this. The answer key says it is 24b^2 but I can't get that

Beginning Alegbra - Nicole-Marie, Saturday, September 15, 2007 at 11:50pm
Oh wait, the answer is just 24b. I wrote the wrong answer. But I can't get that either.
Beginning Alegbra - mathstudent, Sunday, September 16, 2007 at 12:01am
(2b^3)^3 * 3(b^-4)^2
step #1) = 8b^9 * 3b^-8
step #2) = 24b

Explanation:

step 1: (2^3 is 8, b^3^3 = b^9, b^-4^2 = b^-8)

step 2: Multiply the coefficients (8*3=24). Muliply the b terms: b^9 * b^-8 = b^1 = b

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