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September 21, 2014

September 21, 2014

Posted by **Jessica** on Saturday, September 15, 2007 at 5:37pm.

Find the inverese of the one to one function.

16. f(x)= 4/(5x-1)

This is what I've done so far.

y=4/(5x-1)

x= 4/(5y-1)

(5y-1)x= 4(5y-1)

Then I am not too sure what to do next.

- One to one functions -
**bobpursley**, Saturday, September 15, 2007 at 5:46pmThe last line is wrong:

(5y-1)x= 4

5yx= 4+x

y= (x+4)/5x

- One to one functions- Re-Check -
**Soly**, Saturday, September 15, 2007 at 5:59pmy=(x+4)/5x, doesnt match up with what I am suppose to get.

I am suppose to get:

a. f^-1(x)=4/(5y) +1/5, b. f^-1(x)=4/(5x) +1/(5), c. f^-1(x)= -1/(5) -4/(5x), or d. f^-1(x)=5x-1/(4)

- One to one functions -
**bobpursley**, Saturday, September 15, 2007 at 6:34pmy=(x+4)/5x= 1/5 +4/5x

x=1/5+4/5y

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