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August 27, 2014

August 27, 2014

Posted by **COFFEE** on Friday, September 14, 2007 at 8:09pm.

Fiber Linear Density = 1 denier = 1 g/9000m

Fiber Density = 1.14 g/cm^3

[Find..]

Fiber surface area in cm^2/g

Assume that the fiber strand is a uniform cylinder

[Answer]

Surface area = 3,150 cm^2/g

....... how do i get to the answer? my professor gives us these notes:

Pi*D*L

Pi*D is the diameter of the top of the cylinder when it is cut vertically in half. and L is the height.

((Pi*D^2)/(4)) * L = volume of the cylinder

((Pi*D^2)/(4)) * L * Density = weight

..please help!

- Surface Area -
**bobpursley**, Friday, September 14, 2007 at 8:30pmIf it is a cylinder of length L

volume= PI r^2 *L

Surface area= PI*2(r)L

mass=masslineardensiy*L

density= mass/volume=1.14g/cm^3

fiberarea/g= fiberarea/mass=

PI*2*r*L/massdensity*V=

PI*2r*L/(1.14g/cm^2 * PI*r^2*L)

2cm^2/(1.14g*r)= 2/1.14r g/cm^2

Now, r

linear density=1g/9000m

= mass/L= volumedensity*volume/L

1g/9000m=1.14g/cm^3*PIr^2/L

r^2=1cm^3/(1.14*9000m*PI)

=1/(1.14*900000*PI) cm^2

t hen find the sqrt root of that.

final answer= 2/(1.14r) and it will give you your answer.

- Surface Area -
**goh han liang**, Friday, September 5, 2008 at 7:59amhow to do surface area

- Surface Area -

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