Posted by **nick** on Friday, September 14, 2007 at 8:50am.

tank of water with L=6m, W=3m, H=4m.

1) Find the force on the bottom of the tank from water. (ignore atmosphere pressure).

2) If the door to the tank is 1.5m by 1.5m and it is 2.25m (center bottom)from the edge of the tank, what is the force on the door and the position of force from bottom of tank.

Please help me solve these questions!

- physics -
**bobpursley**, Friday, September 14, 2007 at 9:05am
wouldn't the force on the bottom equal the weight of the water?

WEight=volume*density*g

Now figure the pressure at the bottom: Pressure= weight/areabottom

Force on door= pressure*areadoor

- physics -
**nick**, Friday, September 14, 2007 at 9:12am
I though about the volume, this is what I have: F=72m^3x1000Km^3x9.8= 705600 KN/m^3

or 705.6 N/m^3. Is this right or no need to consider gravity?

- physics -
**bobpursley**, Friday, September 14, 2007 at 9:17am
weight is volume*density*g

g is 9.8N/kg density is kg/m^3

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