A hot-air balloonist, rising vertically with a constant velocity of magnitude v = 5.00 m/s, releases a sandbag at an instant when the balloon is a height h = 40.0 m above the ground. After it is released, the sandbag is in free fall. For the questions that follow, take the origin of the coordinate system used for measuring displacements to be at the ground, and upward displacements to be positive.
a)Compute the position of the sandbag at a time 0.290 s after its release.
b)Compute the velocity of the sandbag at a time .290s after its release.
e)How many seconds after its release will the bag strike the ground. (i have worked out to be 3.41s.)
f)with what magnitude of velocity does it strike?
G)what is the greatest height above the ground that the sandbag reaches?
Physics 1 - Douchan, Thursday, September 13, 2007 at 9:56pm
Ok I finally messed around and somehow got E, F, and G can someone please help me with a and b?????