Posted by **Douchan** on Thursday, September 13, 2007 at 12:47pm.

A subway train starts from rest at a station and accelerates at a rate of 1.60m/s^2 for 14.0 s. It runs at constant speed for 70.0 s and slows down at a rate of 3.50m/s^2 until it stops at the next station.

What is the total distance covered?

- Physics 1 -
**bobpursley**, Thursday, September 13, 2007 at 3:05pm
distance:

first leg: avg velocity= 1/2 1.6*14

second leg: avg velocity = 1.6*14

third leg: avg veloctiy= 1/2 * (1.6*14)

multiply each of these by the time for the leg, then add the distances.

- Physics 1 -
**Douchan**, Thursday, September 13, 2007 at 10:09pm
I am really confused as to what you are doing here.

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